Last time we did match-ups between five individuals and found there is a 31% probability that one player can win all matches. This time, we evaluate it using statistical principles.
What is the probability that a specific individual (e.g., player 1) wins all four matches? It is P(1) = (1/2).(1/2).(1/2).(1/2) = (1/16). It is not difficult to recognise that only one among them gets that chance. If one gets all wins, no one else will (chances of 100% wins are mutually exclusive).
So, the probablity of one player winning all is P(1) + P(2) + P(3) + P(4) + P(5) = 5/16 = 0.312.
