Probability of Rain

It’s been a while, so let’s do a probability problem. I found this one in the youtube channel “MindYourDecisions“. If it rains on a day, the probability of rain tomorrow increases by 10%; if not, it reduces by 10% for the next day. What is the probability that it will rain forever within a few days if the chance to rain today is 60%?

Let Px be the chance of raining forever, starting from a day x% rain. We can write the following equations. Note that P100 means it will rain today and every day from there. On the other hand, P0 suggest no rain today and, as a result, it continues.

P1001
P900.9P100 + 0.1P80
P800.8P90 + 0.2P70
P700.7P80 + 0.3P60
P600.6P70 + 0.4P50
P500.5P60 + 0.5P40
P400.4P50 + 0.6P30
P300.3P40 + 0.7P20
P200.2P30 + 0.8P10
P100.1P20 + 0.9P0
P00

Substituting the end value (P0 = 0) for the term P10 and working upwards,

P1001
P900.9P100 + 0.1P800.998P100
P800.8P90 + 0.2P700.98P90
P700.7P80 + 0.3P600.93P80
P600.6P70 + 0.4P500.82P70
P500.5P60 + 0.5P400.67P60
P400.4P50 + 0.6P300.51P50
P300.3P40 + 0.7P200.35P40
P200.2P30 + 0.8P100.22P30
P100.1P20 + 0.9P00.1P20
P00

The value of the last term, 0.998P100 can be evaluated by substituting P100 = 1. Repeating the exercise, now downwards,

P1001
P900.9P100 + 0.1P800.998P1000.998
P800.8P90 + 0.2P700.98P900.98
P700.7P80 + 0.3P600.93P800.91
P600.6P70 + 0.4P500.82P700.75
P500.5P60 + 0.5P400.67P600.55
P400.4P50 + 0.6P300.51P500.34
P300.3P40 + 0.7P200.35P400.18
P200.2P30 + 0.8P100.22P300.08
P100.1P20 + 0.9P00.1P200.02
P00

Therefore, the required probability is 75%.