Going for Three Pointer – Continued

Team A (Defend)
Defend 2Defend 3
Team B
(Shoot)
Shoot 2(0.18, 0.82)(0.31, 0.69)
Shoot 3(0.50, 0.50)(0.23, 0.77)

Let p be the probability for the shooting team to shoot a 3-pointer. The optimal value of p is such that the defending team get no incentive to defend a two over three.

The defensive team’s incentive to defend two = 0.82 (1-p) + 0.5 p
The defensive team’s incentive to defend three = 0.69 (1-p) + 0.77 p
Equating,
0.82 (1-p) + 0.5 p = 0.69 (1-p) + 0.77 p
0.82 p – 0.5 p – 0.69 p + 0.77 p = 0.82 – 0.69
p = 0.325

Let q be the probability for the defending team to defend a 3-pointer. At the optimal value of q, the shooting team get no incentive to shoot a two over three.

The shooting team’s incentive to shoot two = 0.18 (1-q) + 0.31 q
The shooting team’s incentive to shoot three = 0.5 (1-q) + 0.23 q
Equating,
0.18 (1-q) + 0.31 q = 0.5 (1-q) + 0.23 q
0.18 q – 0.31 q – 0.5 q + 0.23 p = 0.18 – 0.5
q = 0.8

Reference

Game theory applied to basketball by Shawn Ruminski: Mind Your Decisions.