From a group of five married couples, how many committees of four or five people can be formed if no two people on the committee may be married to each other?
4-member commitee
There are 5C4 ways to choose four couples. Then there are 2C1 ways to pick one person from each couple.
5C4 x 2C1 x 2C1 x 2C1 x 2C1 = 5 x 2 x 2 x 2 x 2 = 80
5-member commitee
5C5 x 2C1 x 2C1 x 2C1 x 2C1 x 2C1 = 1 x 2 x 2 x 2 x 2 x 2 = 32
The required combinations (OR = union) = 80 + 32 = 112
Without those restrictions, there could have been 10C4 + 10C5 possibilities.